User talk:Arnout aka The Emperors Angel/Explosion, or Fireball?

Explosions can only happen in sealed containers under pressure. If there is an exit hole you get a jet of fire, and usually not an explosion, because the expanding gasses have an escape route. If there is no exit, the usually solid or liquid fuel will vaporize and burn, assuming sufficient oxygen, and keep doing that until the fuel is extinguished or the container fails. Usually you then just get a jet, explosions require the entire container to fail at once.--Łô√ë îğá†ħŕášħ 16:35, 12 July 2011 (UTC)
 * True. But I'm not sure what you are getting at. I was already busy explaining why the casus wasn't an explosion, but rather, a big FIREBALL! Arnout aka The Emperors Angel 16:51, 12 July 2011 (UTC)


 * If you say explosions only happen in pressurized containers, what do you call it when dynamite or any other kind of explosive blows up? &mdash; Viruzzz 18:57, 12 July 2011 (UTC)
 * I think, that he was merely adding conditions for the gascontainer to explode. Arnout aka The Emperors Angel 19:00, 12 July 2011 (UTC)
 * (EC) Dynamite, C4, and Nitroglycerin are one category of explosives, with grenades and bombs compromising another, with other volatiles with their one class. Dynamite and associated do not need pressurized containers because they are able to burn all at once, condensing the entire reaction into a very short amount of time.  Grenades are self contained and build up pressure inside, but use a very similar manner to the more dangerous explosives.  The final category (hereafter refereed to as the Red Gas Barrel category) is simply not volatile and inflammable enough to support rapid expansion after simply being lit on fire.  The pressure is needed to contain the reaction long enough for the gas to build up and then break the container.  Which then produces the fireball as all that new gas goes through the reaction (CxH2x+1.5XO2=>XCO2+XH2O).--Łô√ë [[Image:Gigathrash_sig_G.jpg]]îğá†ħŕášħ  19:13, 12 July 2011 (UTC)
 * Yay, Giga has joined my side! MUHAHAHA. You mind if I put it up on the page? It's better than whatever I wrote... Arnout aka The Emperors Angel 19:19, 12 July 2011 (UTC)
 * Go ahead, but it should be noted that that formula only works in excess oxygen with -ane hydrocarbons and does not work for methane.--Łô√ë [[Image:Gigathrash_sig_G.jpg]]îğá†ħŕášħ 19:28, 12 July 2011 (UTC)


 * Unless you're talking about cyclic alkanes (which aren't usually the first choice for examples of combustion), the formula should be CxH(2x+2) for a linear alkane. CxH2x is a cyclic alkane or an alkene.  &mdash;Dr Ishmael Diablo_the_chicken.gif 19:40, 12 July 2011 (UTC)
 * Oops, Ish is correct.--Łô√ë [[Image:Gigathrash_sig_G.jpg]]îğá†ħŕášħ 22:12, 12 July 2011 (UTC)


 * I think that also screws up the coefficients in the rest of the reaction, but I don't have time for the math right now. Wikipedia's article has a completely generic equation for any hydrocarbon.  &mdash;Dr Ishmael Diablo_the_chicken.gif 22:18, 12 July 2011 (UTC)

Well, we can always do something like this: CH4+2O2=>CO2+2H2O 2C2H6+7O2=>4CO2+6H2O C3H8+5O2=>3CO2+4H2O 2C4H10+13O2=>8CO2+10H2O C5H12+8O2=>5CO2+6H2O 2C6H14+19O2=>12CO2+14H2O C7H16+11O2=>7CO2+8H2O 2C8H18+25O2=>16CO2+18H2O C9H20+14O2=>9CO2+10H2O 2C10H22+29O2=>20CO2+22H2O --Łô√ë îğá†ħŕášħ 22:41, 12 July 2011 (UTC)